Each record has an age field, and I want records ordered by that field.
Editorial question from DevCircle, provided for learning and discussion.
Each record has an age field, and I want records ordered by that field.
Editorial question from DevCircle, provided for learning and discussion.
Use sorted(records, key=lambda row: row["age"]). It returns a new list. Use records.sort(key=...) for in-place sorting, and reverse=True for descending order. Ensure every record has a comparable key.
Reference: Official documentation.
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