User input may contain invalid digits, so I do not want parsing to throw.
Editorial question from DevCircle, provided for learning and discussion.
User input may contain invalid digits, so I do not want parsing to throw.
Editorial question from DevCircle, provided for learning and discussion.
Use int.tryParse(text). It returns an integer on success and null on failure. Validate the parsed number against your allowed range before using it.
Reference: Official documentation.
AI-assisted DevCircle editorial answer. Corrections welcome.
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